What is the integral from-2 to 1 of (4x^4-x) ?

The integral from-2 to 1 of (4x^4-x) is 279/10

Popular >

integral from-2 to 1 of (4x^4-x)

\int_{- 2}^{1} (4 x^{4} - x) d x

\frac{279}{10}

Decimal

27.9

Solution steps

\int_{- 2}^{1} 4 x^{4} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 4 x^{4} d x - \int_{- 2}^{1} x d x

\int_{- 2}^{1} 4 x^{4} d x = \frac{132}{5}

\int_{- 2}^{1} x d x = - \frac{3}{2}

= \frac{132}{5} - (- \frac{3}{2})

Simplify

\frac{132}{5} - (- \frac{3}{2}) : \frac{279}{10}

= \frac{279}{10}

\int_{\frac{π}{4}}^{\frac{π}{3}} cos (x) d x

\int_{- 1}^{1} (x + 1) e^{∣ x ∣} d x

\int_{0}^{1} 5 x^{3} 1 - x^{2} d x

\int_{0}^{1} \frac{ln ( 1 + t )}{1 + t} d t

\int_{0}^{4} \frac{e ^{x}}{4 + e ^{x}} d x

What is the integral from-2 to 1 of (4x^4-x) ?
The integral from-2 to 1 of (4x^4-x) is 279/10