What is the integral from 0 to 3 of (3x)-(x^2) ?

The integral from 0 to 3 of (3x)-(x^2) is 9/2

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integral from 0 to 3 of (3x)-(x^2)

\int_{0}^{3} (3 x) - (x^{2}) d x

\frac{9}{2}

Decimal

4.5

Solution steps

\int_{0}^{3} 3 x - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 3 x d x - \int_{0}^{3} x^{2} d x

\int_{0}^{3} 3 x d x = \frac{27}{2}

\int_{0}^{3} x^{2} d x = 9

= \frac{27}{2} - 9

Simplify

\frac{27}{2} - 9 : \frac{9}{2}

= \frac{9}{2}

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What is the integral from 0 to 3 of (3x)-(x^2) ?
The integral from 0 to 3 of (3x)-(x^2) is 9/2