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Popular >

integral from 0 to 2 of (4x+1)

Solution

\int_{0}^{2} (4 x + 1) d x

Solution

10

Solution steps

\int_{0}^{2} 4 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 4 x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} 4 x d x = 8

\int_{0}^{2} 1 d x = 2

= 8 + 2

Simplify

= 10

Graph

Popular Examples

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\int_{0}^{1} \frac{sin ( x ^{4} )}{x ^{4}} d x

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\int_{0}^{3} (6 x - x^{2}) - x^{2} d x

integral from-10 to 10 of x

\int_{- 10}^{10} x d x

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\int_{0}^{3} \frac{1}{2} x d x

integral from 0 to 8 of (\sqrt[3]{x})^2

\int_{0}^{8} (3 x)^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (4x+1) ?
The integral from 0 to 2 of (4x+1) is 10