What is the integral from 6 to 4 of 1 ?

The integral from 6 to 4 of 1 is -2

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integral from 6 to 4 of 1

\int_{6}^{4} 1

- 2

Solution steps

\int_{6}^{4} 1 d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{4}^{6} 1 d x

Integral of a constant:

\int a d x = a x

= - [1 \cdot x]_{4}^{6}

Simplify

= - [x]_{4}^{6}

Compute the boundaries:

2

= - 2

\int_{- 2}^{2} 8 - x^{3} d x

\int_{- 1}^{3} (3 x - 1) d x

\int_{- π}^{π} x \cdot cos (x) d x

\int_{0}^{3} x - 2 d x

\int_{1}^{2} (1 - x)^{3} d x