What is the integral from 0 to 2 of kx^3 ?

The integral from 0 to 2 of kx^3 is k*4

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integral from 0 to 2 of kx^3

\int_{0}^{2} k x^{3} d x

k \cdot 4

Solution steps

\int_{0}^{2} k x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{0}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{2}

= k [\frac{x ^{4}}{4}]_{0}^{2}

Compute the boundaries:

4

= k \cdot 4

\int_{2}^{3} (x + 1) (x^{2} + 2 x)^{3} d x

\int_{0}^{π} (sin (x))^{5} d x

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\int_{0}^{π} 2 + sin (x) d x

\int_{2}^{3} \frac{1}{1 - x} d x

What is the integral from 0 to 2 of kx^3 ?
The integral from 0 to 2 of kx^3 is k*4