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Popular >

integral from-2 to 0 of 8x^2+8x

Solution

\int_{- 2}^{0} 8 x^{2} + 8 x d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{- 2}^{0} 8 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} 8 x^{2} d x + \int_{- 2}^{0} 8 x d x

\int_{- 2}^{0} 8 x^{2} d x = \frac{64}{3}

\int_{- 2}^{0} 8 x d x = - 16

= \frac{64}{3} - 16

Simplify

\frac{64}{3} - 16 : \frac{16}{3}

= \frac{16}{3}

Graph

Popular Examples

integral from-4 to 4 of 2sqrt(16-x^2)

\int_{- 4}^{4} 2 16 - x^{2} d x

integral from cos(x) to 5x of cos(u^3)

\int_{c o s (x)}^{5 x} cos (u^{3}) d u

integral from-3 to-2 of 2x(5-x^2)^3

\int_{- 3}^{- 2} 2 x (5 - x^{2})^{3} d x

integral from 9 to 18 of xsqrt(x-9)

\int_{9}^{18} x x - 9 d x

integral from pi/6 to pi/2 of (cos(x))^2

\int_{\frac{π}{6}}^{\frac{π}{2}} (cos (x))^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 0 of 8x^2+8x ?
The integral from-2 to 0 of 8x^2+8x is 16/3