What is the integral of (sec^2(x)+4) ?

The integral of (sec^2(x)+4) is tan(x)+4x+C

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integral of (sec^2(x)+4)

\int (sec^{2} (x) + 4) d x

tan (x) + 4 x + C

Solution steps

\int sec^{2} (x) + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x + \int 4 d x

\int sec^{2} (x) d x = tan (x)

\int 4 d x = 4 x

= tan (x) + 4 x

Add a constant to the solution

= tan (x) + 4 x + C

\int \frac{( 1 - x )}{x} d x

\int (4 t^{2} + 3)^{2} d t

\int (x - e^{x})^{2} d x

y^{^{'}} = 2 (x + y)^{2}

What is the integral of (sec^2(x)+4) ?
The integral of (sec^2(x)+4) is tan(x)+4x+C