What is the integral from 1 to 12 of 4/(x^2) ?

The integral from 1 to 12 of 4/(x^2) is 11/3

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integral from 1 to 12 of 4/(x^2)

\int_{1}^{12} \frac{4}{x ^{2}} d x

\frac{11}{3}

Decimal

3.66666 \dots

Solution steps

\int_{1}^{12} \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{12} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{12}

= 4 [- \frac{1}{x}]_{1}^{12}

Compute the boundaries:

\frac{11}{12}

= 4 \cdot \frac{11}{12}

Simplify

= \frac{11}{3}

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What is the integral from 1 to 12 of 4/(x^2) ?
The integral from 1 to 12 of 4/(x^2) is 11/3