What is the integral from 1 to 2 of-1/z ?

The integral from 1 to 2 of-1/z is -ln(2)

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integral from 1 to 2 of-1/z

\int_{1}^{2} - \frac{1}{z} d z

- ln (2)

Decimal

- 0.69314 \dots

Solution steps

\int_{1}^{2} - \frac{1}{z} d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{1}^{2} \frac{1}{z} d z

Use the common integral:

\int \frac{1}{z} d z = ln (∣ z ∣)

= - [ln ∣ z ∣]_{1}^{2}

Compute the boundaries:

ln (2)

= - ln (2)

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\int_{0}^{200} x e^{- \frac{x}{12}} d x

What is the integral from 1 to 2 of-1/z ?
The integral from 1 to 2 of-1/z is -ln(2)