What is the integral from-1 to 1 of rsqrt(25-r^2) ?

The integral from-1 to 1 of rsqrt(25-r^2) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of rsqrt(25-r^2)

\int_{- 1}^{1} r 25 - r^{2} d r

0

Solution steps

\int_{- 1}^{1} r 25 - r^{2} d r

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

r 25 - r^{2} :

Odd

= 0

\int_{2}^{3} (x^{2} e^{x^{3} - 8}) d x

\int_{0}^{2 π} \frac{1}{2} (3 + 3 cos (x))^{2} d x

\int_{0}^{3} t^{2} + 4 t - 5 d t

\int_{0}^{1} (x^{2} - x^{3})^{2} d x

\int_{- 2}^{0} x^{2} - 10 x d x

What is the integral from-1 to 1 of rsqrt(25-r^2) ?
The integral from-1 to 1 of rsqrt(25-r^2) is 0