What is the integral from 0 to infinity of e^{t-st} ?

The integral from 0 to infinity of e^{t-st} is Undefined-1/(1-s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to infinity of e^{t-st}

\int_{0}^{\infty} e^{t - s t} d t

Undefined - \frac{1}{1 - s}

Solution steps

\int_{0}^{\infty} e^{t - s t} d t

Compute the indefinite integral:

\int e^{t - s t} d t = \frac{1}{1 - s} e^{t - s t} + C

Compute the boundaries:

\int_{0}^{\infty} e^{t - s t} d t =

Undefined

- \frac{1}{1 - s}

= Undefined - \frac{1}{1 - s}

\int_{1}^{2} \frac{arccsc ( x )}{6} d x

\int_{0}^{y} 10 x y^{2} d x

\int_{0}^{1} 9 x^{8} (4 - x^{9}) d x

\int_{4}^{10} b x^{2} d x

\int_{1}^{3} \frac{x ^{2}}{x ^{3} - 27} d x

What is the integral from 0 to infinity of e^{t-st} ?
The integral from 0 to infinity of e^{t-st} is Undefined-1/(1-s)