What is the integral from 0 to 2 of (x-3)^3 ?

The integral from 0 to 2 of (x-3)^3 is -20

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integral from 0 to 2 of (x-3)^3

\int_{0}^{2} (x - 3)^{3} d x

- 20

Solution steps

\int_{0}^{2} (x - 3)^{3} d x

Apply u-substitution

: \int_{- 3}^{- 1} u^{3} d u

= \int_{- 3}^{- 1} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{- 3}^{- 1}

= [\frac{u ^{4}}{4}]_{- 3}^{- 1}

Compute the boundaries:

- 20

= - 20

\int_{1}^{2} 3 - x - \frac{2}{x} d x

\int_{2}^{x} (t^{3} + 4 t - 2) d t

\int_{0}^{s} 40 s^{\frac{1}{2}} d s

\int_{1}^{4} 9 x d x

\int_{1}^{8} 2 lo g_{4} (t + 3) d t

What is the integral from 0 to 2 of (x-3)^3 ?
The integral from 0 to 2 of (x-3)^3 is -20