What is the integral from 1 to infinity of x/(x^2) ?

The integral from 1 to infinity of x/(x^2) is diverges

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integral from 1 to infinity of x/(x^2)

\int_{1}^{\infty} \frac{x}{x ^{2}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{x}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2}} d x = ln ∣ x ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{x}{x ^{2}} d x =

diverges

= diverges

\int_{0}^{1} \frac{1}{2 - x} d x

\int_{- 3}^{0} x f (x^{2}) d x

\int_{- 2}^{2} (5 - 3 4 - x^{2}) d x

\int_{0}^{1} 6 6 x d x

\int_{2}^{5} 8 x - 16 d x

What is the integral from 1 to infinity of x/(x^2) ?
The integral from 1 to infinity of x/(x^2) is diverges