What is the solution for y^'+e^xy=x^2y^2 ?

The solution for y^'+e^xy=x^2y^2 is y= 1/(e^{e^x)*integral of-e^{-e^x}x^2}

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y^'+e^xy=x^2y^2

y^{^{'}} + e^{x} y = x^{2} y^{2}

y = \frac{1}{e ^{e^{x}} \cdot \int - e ^{- e^{x}} x ^{2} d x}

Solution steps

y^{'} (x) + e^{x} y = x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{1}{e ^{e^{x}} \cdot \int - e ^{- e^{x}} x ^{2} d x}

y = \frac{1}{e ^{e^{x}} \cdot \int - e ^{- e^{x}} x ^{2} d x}

y = x^{2}, y = 17 x

\int_{0}^{1} \frac{e ^{x}}{e ^{x} + 1} d x

\frac{\partial}{\partial x} (a sin (w (x) x) + b cos (w (x) x))

x - x^{\frac{1}{2}}

\frac{d}{d x} ((x^{2}) (2 x^{3} + x)^{3})

What is the solution for y^'+e^xy=x^2y^2 ?
The solution for y^'+e^xy=x^2y^2 is y= 1/(e^{e^x)*integral of-e^{-e^x}x^2}