What is the integral from x^2-1 to x^2+1 of f(t) ?

The integral from x^2-1 to x^2+1 of f(t) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from x^2-1 to x^2+1 of f(t)

\int_{x^{2} - 1}^{x^{2} + 1} f (t) d t

0

Solution steps

\int_{x^{2} - 1}^{x^{2} + 1} f t d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

f t :

Odd

= 0

\int_{10}^{1} \frac{1}{x ^{2}} d x

\int_{0}^{t} e^{- 2 (t - x)} d x

\int_{\frac{π}{4}}^{\frac{π}{2}} csc^{4} (x) d x

\int_{1}^{3} y d y

\int_{0}^{\frac{π}{2}} 8 cos (t) sin (t) d t

What is the integral from x^2-1 to x^2+1 of f(t) ?
The integral from x^2-1 to x^2+1 of f(t) is 0