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Popular >

integral from 1 to 2 of 2-t

Solution

\int_{1}^{2} 2 - t d t

Solution

\frac{1}{2}

+1

Decimal

0.5

Solution steps

\int_{1}^{2} 2 - t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 d t - \int_{1}^{2} t d t

\int_{1}^{2} 2 d t = 2

\int_{1}^{2} t d t = \frac{3}{2}

= 2 - \frac{3}{2}

Simplify

2 - \frac{3}{2} : \frac{1}{2}

= \frac{1}{2}

Graph

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\int_{1.5}^{3} (- \frac{x}{3} + 1) d x

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\int_{0}^{\frac{π}{2}} 16 cos (x) d x

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\int_{- 5}^{5} \frac{6}{x ^{3}} d x

integral from-2 to 0 of-4x

\int_{- 2}^{0} - 4 x d x

integral from 0 to t of cos(2t)

\int_{0}^{t} cos (2 t) d t

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of 2-t ?
The integral from 1 to 2 of 2-t is 1/2