en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of-x-1

Solution

\int_{- 1}^{1} - x - 1 d x

Solution

- 2

Solution steps

\int_{- 1}^{1} - x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{1} x d x - \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 1 d x = 2

= - 0 - 2

Simplify

= - 2

Graph

Popular Examples

integral from 0 to 2 of 2pix(8x(x-2)^2)

\int_{0}^{2} 2 π x (8 x (x - 2)^{2}) d x

integral from 0 to 2 of 2x+x^2

\int_{0}^{2} 2 x + x^{2} d x

integral from-8 to 2 of sqrt(16-6x-x^2)

\int_{- 8}^{2} 16 - 6 x - x^{2} d x

integral from 0 to infinity of |sin(x)|

\int_{0}^{\infty} ∣ sin (x) ∣ d x

integral from-5 to 5 of-sqrt(25-x^2)

\int_{- 5}^{5} - 25 - x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of-x-1 ?
The integral from-1 to 1 of-x-1 is -2