What is the integral from-1 to 1 of (2x) ?

The integral from-1 to 1 of (2x) is 0

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integral from-1 to 1 of (2x)

\int_{- 1}^{1} (2 x) d x

0

Solution steps

\int_{- 1}^{1} 2 x d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

2 x :

Odd

= 0

\int_{0.43}^{x} \frac{1}{( 1 - x ) ^{2}} d x

\int_{x}^{x} cos (t^{2}) d t

\int_{0}^{\infty} c e^{- 2 x} d x

\int_{0}^{3} \frac{3000}{1 + 0.25 t} d t

\int_{- 2}^{1} - x^{4} - x^{2} - 6 x + 8 d x

What is the integral from-1 to 1 of (2x) ?
The integral from-1 to 1 of (2x) is 0