What is the integral from 0 to 1 of (2x^2-2x) ?

The integral from 0 to 1 of (2x^2-2x) is -1/3

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integral from 0 to 1 of (2x^2-2x)

\int_{0}^{1} (2 x^{2} - 2 x) d x

- \frac{1}{3}

Decimal

- 0.33333 \dots

Solution steps

\int_{0}^{1} 2 x^{2} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 x^{2} d x - \int_{0}^{1} 2 x d x

\int_{0}^{1} 2 x^{2} d x = \frac{2}{3}

\int_{0}^{1} 2 x d x = 1

= \frac{2}{3} - 1

Simplify

\frac{2}{3} - 1 : - \frac{1}{3}

= - \frac{1}{3}

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What is the integral from 0 to 1 of (2x^2-2x) ?
The integral from 0 to 1 of (2x^2-2x) is -1/3