What is the solution for y^'= y/x+(y^2)/(x^2) ?

The solution for y^'= y/x+(y^2)/(x^2) is y= x/(-ln(x)+c_{1)}

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y^'= y/x+(y^2)/(x^2)

y^{^{'}} = \frac{y}{x} + \frac{y ^{2}}{x ^{2}}

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

y^{'} (x) = \frac{y}{x} + \frac{y ^{2}}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

- \frac{1}{2} y^{^{'}} + y = 4

28 x (4 x^{2} + 9)^{\frac{5}{2}}

x lo g_{3} (x)

\frac{d}{d x} (\frac{2}{3} (1 + x)^{\frac{3}{2}})

\frac{\partial}{\partial x} (4 y cos (x y))

What is the solution for y^'= y/x+(y^2)/(x^2) ?
The solution for y^'= y/x+(y^2)/(x^2) is y= x/(-ln(x)+c_{1)}