What is the integral from-e^8 to-e^6 of 1/x ?

The integral from-e^8 to-e^6 of 1/x is -2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-e^8 to-e^6 of 1/x

\int_{- e^{8}}^{- e^{6}} \frac{1}{x} d x

- 2

Solution steps

\int_{- e^{8}}^{- e^{6}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{- e^{8}}^{- e^{6}}

Compute the boundaries:

- 2

= - 2

\int_{0}^{π} cos (2 x) cos (n x) d x

\int_{- 1}^{3} 1 - x d x

\int_{0}^{1} \frac{x}{x ^{2} + 5 x + 6} d x

\int_{- 1}^{1} x e^{- x^{2}} d x

\int_{0}^{\frac{π}{3}} cos^{2} (θ) d θ

What is the integral from-e^8 to-e^6 of 1/x ?
The integral from-e^8 to-e^6 of 1/x is -2