What is the integral from-1 to 3 of (3x^2-x-6) ?

The integral from-1 to 3 of (3x^2-x-6) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 3 of (3x^2-x-6)

\int_{- 1}^{3} (3 x^{2} - x - 6) d x

0

Solution steps

\int_{- 1}^{3} 3 x^{2} - x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} 3 x^{2} d x - \int_{- 1}^{3} x d x - \int_{- 1}^{3} 6 d x

\int_{- 1}^{3} 3 x^{2} d x = 28

\int_{- 1}^{3} x d x = 4

\int_{- 1}^{3} 6 d x = 24

= 28 - 4 - 24

Simplify

= 0

\int_{0}^{1} 7 x^{3} 1 - x^{2} d x

\int_{4}^{1} x d x

\int_{0}^{3} x (8 x^{2} + 9)^{\frac{1}{2}} d x

\int_{1}^{3} (2 x^{2} + 1) d x

\int_{2}^{6} 8 x - 24 d x

What is the integral from-1 to 3 of (3x^2-x-6) ?
The integral from-1 to 3 of (3x^2-x-6) is 0