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Popular >

integral from 0 to 4 of-x^2+2x+1

Solution

\int_{0}^{4} - x^{2} + 2 x + 1 d x

Solution

- \frac{4}{3}

+1

Decimal

- 1.33333 \dots

Solution steps

\int_{0}^{4} - x^{2} + 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{4} x^{2} d x + \int_{0}^{4} 2 x d x + \int_{0}^{4} 1 d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 1 d x = 4

= - \frac{64}{3} + 16 + 4

Simplify

- \frac{64}{3} + 16 + 4 : - \frac{4}{3}

= - \frac{4}{3}

Graph

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\int_{0}^{π} sin (n x + x) d x

integral from 0 to 1/4 of sqrt(x)sin(x)

\int_{0}^{\frac{1}{4}} x sin (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of-x^2+2x+1 ?
The integral from 0 to 4 of-x^2+2x+1 is -4/3