What is the integral from 1 to infinity of x^2+x+1 ?

The integral from 1 to infinity of x^2+x+1 is diverges

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integral from 1 to infinity of x^2+x+1

\int_{1}^{\infty} x^{2} + x + 1 d x

diverges

Solution steps

\int_{1}^{\infty} x^{2} + x + 1 d x

Compute the indefinite integral:

\int x^{2} + x + 1 d x = \frac{x ^{3}}{3} + \frac{x ^{2}}{2} + x + C

Compute the boundaries:

\int_{1}^{\infty} x^{2} + x + 1 d x =

diverges

= diverges

\int_{0}^{2} 2 e^{x^{2} - x} d x

\int_{0}^{\frac{π}{4}} 16 cos^{2} (x) d x

\int_{0}^{24} x x + a d x

\int_{0}^{1} \frac{sin ( x )}{x ^{2}} d x

\int_{x}^{0} cos (t^{2}) d t

What is the integral from 1 to infinity of x^2+x+1 ?
The integral from 1 to infinity of x^2+x+1 is diverges