What is the integral from pi/2 to pi of (sin(x)) ?

The integral from pi/2 to pi of (sin(x)) is 1

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integral from pi/2 to pi of (sin(x))

\int_{\frac{π}{2}}^{π} (sin (x)) d x

1

Solution steps

\int_{\frac{π}{2}}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{\frac{π}{2}}^{π}

Compute the boundaries:

1

= 1

\int_{0}^{2} \frac{x}{1 + 4 x ^{2}} d x

\int_{0}^{1} 5 x^{4} (6 - x^{5}) d x

\int_{0}^{1} (1 - 2 x) d x

\int_{1}^{2} \frac{1}{x} + x d x

\int_{0}^{\frac{π}{2}} \frac{1 + cos ( 2 x )}{2} d x

What is the integral from pi/2 to pi of (sin(x)) ?
The integral from pi/2 to pi of (sin(x)) is 1