What is the integral from 0 to 1 of x*x^2 ?

The integral from 0 to 1 of x*x^2 is 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of x*x^2

\int_{0}^{1} x \cdot x^{2} d x

\frac{1}{4}

Decimal

0.25

Solution steps

\int_{0}^{1} x x^{2} d x

Simplify

x x^{2} : x^{3}

= \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= \frac{1}{4}

\int_{1}^{6} x^{2} x + 3 d x

\int_{- 3}^{3} x^{3} - 9 x d x

\int_{0}^{π} 4 e^{x} + 7 sin (x) d x

\int_{0}^{3} (9 - x^{2})^{3} d x

\int_{- 1}^{1} (x^{2} - \frac{1}{3}) d x

What is the integral from 0 to 1 of x*x^2 ?
The integral from 0 to 1 of x*x^2 is 1/4