What is the integral from-1/2 to 1/2 of (x^3-4x) ?

The integral from-1/2 to 1/2 of (x^3-4x) is 0

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integral from-1/2 to 1/2 of (x^3-4x)

\int_{- \frac{1}{2}}^{\frac{1}{2}} (x^{3} - 4 x) d x

0

Solution steps

\int_{- \frac{1}{2}}^{\frac{1}{2}} x^{3} - 4 x d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{3} - 4 x :

Odd

= 0

\int_{0}^{3} 1 + (2 x)^{2} d x

\int_{2}^{5} 2 x^{2} - cos (2 x) d x

\int_{0}^{7} π sin (\frac{π x}{7}) + 1 d x

\int_{0}^{2} 3 t e^{- s t} d t

\int_{0}^{2} e^{x} - 1 d x

What is the integral from-1/2 to 1/2 of (x^3-4x) ?
The integral from-1/2 to 1/2 of (x^3-4x) is 0