What is the integral from 0 to 9 of (y^3)/9 ?

The integral from 0 to 9 of (y^3)/9 is 729/4

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integral from 0 to 9 of (y^3)/9

\int_{0}^{9} \frac{y ^{3}}{9} d y

\frac{729}{4}

Decimal

182.25

Solution steps

\int_{0}^{9} \frac{y ^{3}}{9} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int_{0}^{9} y^{3} d y

Apply the Power Rule

: [\frac{y ^{4}}{4}]_{0}^{9}

= \frac{1}{9} [\frac{y ^{4}}{4}]_{0}^{9}

Compute the boundaries:

\frac{6561}{4}

= \frac{1}{9} \cdot \frac{6561}{4}

Simplify

= \frac{729}{4}

\int_{0}^{9} \frac{x}{4 + 5 x} d x

\int_{0}^{5} (x - 2)^{3} d x

\int_{- 2}^{3} (3 - ∣ x ∣) d x

\int_{5}^{9} x d x

\int_{3}^{5} \frac{x ^{2} + x + 6}{x - 2} d x

What is the integral from 0 to 9 of (y^3)/9 ?
The integral from 0 to 9 of (y^3)/9 is 729/4