What is the integral from 3 to 7 of (10)/(x^2) ?

The integral from 3 to 7 of (10)/(x^2) is 40/21

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integral from 3 to 7 of (10)/(x^2)

\int_{3}^{7} \frac{10}{x ^{2}} d x

\frac{40}{21}

Decimal

1.90476 \dots

Solution steps

\int_{3}^{7} \frac{10}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int_{3}^{7} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{3}^{7}

= 10 [- \frac{1}{x}]_{3}^{7}

Compute the boundaries:

\frac{4}{21}

= 10 \cdot \frac{4}{21}

Simplify

= \frac{40}{21}

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What is the integral from 3 to 7 of (10)/(x^2) ?
The integral from 3 to 7 of (10)/(x^2) is 40/21