What is the integral from 1 to 3 of 8x^3 ?

The integral from 1 to 3 of 8x^3 is 160

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integral from 1 to 3 of 8x^3

\int_{1}^{3} 8 x^{3} d x

160

Solution steps

\int_{1}^{3} 8 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{1}^{3} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{3}

= 8 [\frac{x ^{4}}{4}]_{1}^{3}

Compute the boundaries:

20

= 8 \cdot 20

Simplify

= 160

\int_{0}^{1} (r + 3) (r - 4) d r

\int_{\frac{1}{2}}^{\frac{1}{3}} (cos (π w)) d w

\int_{- 2}^{3} 1 - x d x

\int_{1}^{\infty} tan (x) d x

\int_{0}^{0.8} e^{x^{2}} d x

What is the integral from 1 to 3 of 8x^3 ?
The integral from 1 to 3 of 8x^3 is 160