What is the integral from 0 to b of cos(x) ?

The integral from 0 to b of cos(x) is sin(b)

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integral from 0 to b of cos(x)

\int_{0}^{b} cos (x) d x

sin (b)

Solution steps

\int_{0}^{b} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{0}^{b}

Compute the boundaries:

sin (b)

= sin (b)

\int_{0}^{\frac{1}{2} l n (3)} e^{2 x} d x

\int_{- 4}^{3} ∣ x + 3 ∣ d x

\int_{3 x}^{x^{5}} e^{- t^{2}} d t

\int_{0}^{2} x^{2} (8 - x^{3}) d x

\int_{0}^{4} 4 x - \frac{x ^{2}}{4} d x

What is the integral from 0 to b of cos(x) ?
The integral from 0 to b of cos(x) is sin(b)