What is the integral from 1 to 2 of (x^3)/3 ?

The integral from 1 to 2 of (x^3)/3 is 5/4

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integral from 1 to 2 of (x^3)/3

\int_{1}^{2} \frac{x ^{3}}{3} d x

\frac{5}{4}

Decimal

1.25

Solution steps

\int_{1}^{2} \frac{x ^{3}}{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{1}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{2}

= \frac{1}{3} [\frac{x ^{4}}{4}]_{1}^{2}

Compute the boundaries:

\frac{15}{4}

= \frac{1}{3} \cdot \frac{15}{4}

Simplify

= \frac{5}{4}

\int_{0}^{3} \frac{1}{3} x d x

\int_{0}^{\frac{π}{2}} 2 x d x

\int_{- 1}^{1} x^{2} e^{x^{2}} d x

\int_{- 2}^{14} \frac{sin ( x )}{x} d x

\int_{0}^{4} \frac{1}{4} x d x

What is the integral from 1 to 2 of (x^3)/3 ?
The integral from 1 to 2 of (x^3)/3 is 5/4