What is the integral from T to T^' of 1 ?

The integral from T to T^' of 1 is T^'-T

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from T to T^' of 1

\int_{T}^{T^{^{'}}} 1 d T

T^{'} - T

Solution steps

\int_{T}^{T^{^{'}}} 1 d T

Integral of a constant:

\int a d x = a x

= [1 \cdot T]_{T}^{T^{^{^{'}}}}

Simplify

= [T]_{T}^{T^{^{^{'}}}}

Compute the boundaries:

T^{^{'}} - T

= T^{^{^{'}}} - T

\int_{1}^{2} x x d x

\int_{0}^{1} 2 - x^{2} - x^{4} d x

\int_{0}^{y} \frac{1}{4} (x + y) d x

\int_{1}^{5} (2 x) d x

\int_{0}^{6} 6 - x^{2} d x

What is the integral from T to T^' of 1 ?
The integral from T to T^' of 1 is T^'-T