What is the integral from 6 to 5 of (sin(x)) ?

The integral from 6 to 5 of (sin(x)) is cos(6)-cos(5)

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integral from 6 to 5 of (sin(x))

\int_{6}^{5} (sin (x)) d x

cos (6) - cos (5)

Decimal

0.67650 \dots

Solution steps

\int_{6}^{5} sin (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{5}^{6} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{5}^{6}

Compute the boundaries:

- cos (6) + cos (5)

= - (- cos (6) + cos (5))

Simplify

= cos (6) - cos (5)

\int_{2}^{8} - \frac{6}{x} d x

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What is the integral from 6 to 5 of (sin(x)) ?
The integral from 6 to 5 of (sin(x)) is cos(6)-cos(5)