What is the integral from b to a of 1/(x^2) ?

The integral from b to a of 1/(x^2) is -1/a+1/b

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integral from b to a of 1/(x^2)

\int_{b}^{a} \frac{1}{x ^{2}} d x

- \frac{1}{a} + \frac{1}{b}

Solution steps

\int_{b}^{a} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{b}^{a}

= [- \frac{1}{x}]_{b}^{a}

Compute the boundaries:

- \frac{1}{a} + \frac{1}{b}

= - \frac{1}{a} + \frac{1}{b}

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What is the integral from b to a of 1/(x^2) ?
The integral from b to a of 1/(x^2) is -1/a+1/b