What is the integral from 1 to 5 of (x/5+y/(20)) ?

The integral from 1 to 5 of (x/5+y/(20)) is x-x/5+3/5

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integral from 1 to 5 of (x/5+y/(20))

\int_{1}^{5} (\frac{x}{5} + \frac{y}{20}) d y

x - \frac{x}{5} + \frac{3}{5}

Solution steps

\int_{1}^{5} \frac{x}{5} + \frac{y}{20} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} \frac{x}{5} d y + \int_{1}^{5} \frac{y}{20} d y

\int_{1}^{5} \frac{x}{5} d y = x - \frac{x}{5}

\int_{1}^{5} \frac{y}{20} d y = \frac{3}{5}

= x - \frac{x}{5} + \frac{3}{5}

\int_{- 3}^{6} 3 x - 5 d x

\int_{0}^{1} (7 x^{2} - 8 x + 6) d x

\int_{1}^{5} x^{2} - 2 x - 15 d x

\int_{1}^{5} (3 x^{2}) d x

\int_{3}^{6} (x - 3)^{2} d x

What is the integral from 1 to 5 of (x/5+y/(20)) ?
The integral from 1 to 5 of (x/5+y/(20)) is x-x/5+3/5