What is the integral from-2 to 2 of (x^4-3x^2) ?

The integral from-2 to 2 of (x^4-3x^2) is -16/5

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integral from-2 to 2 of (x^4-3x^2)

\int_{- 2}^{2} (x^{4} - 3 x^{2}) d x

- \frac{16}{5}

Decimal

- 3.2

Solution steps

\int_{- 2}^{2} x^{4} - 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} x^{4} d x - \int_{- 2}^{2} 3 x^{2} d x

\int_{- 2}^{2} x^{4} d x = \frac{64}{5}

\int_{- 2}^{2} 3 x^{2} d x = 16

= \frac{64}{5} - 16

Simplify

\frac{64}{5} - 16 : - \frac{16}{5}

= - \frac{16}{5}

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What is the integral from-2 to 2 of (x^4-3x^2) ?
The integral from-2 to 2 of (x^4-3x^2) is -16/5