What is the integral from 0 to 1 of e^{sin(x)}cos(x) ?

The integral from 0 to 1 of e^{sin(x)}cos(x) is e^{sin(1)}-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of e^{sin(x)}cos(x)

\int_{0}^{1} e^{s i n (x)} cos (x) d x

e^{s i n (1)} - 1

Decimal

1.31977 \dots

Solution steps

\int_{0}^{1} e^{s i n (x)} cos (x) d x

Apply u-substitution

: \int_{0}^{s i n (1)} e^{u} d u

= \int_{0}^{s i n (1)} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= [e^{u}]_{0}^{s i n (1)}

Compute the boundaries:

e^{s i n (1)} - 1

= e^{s i n (1)} - 1

\int_{0}^{7} 3 t 49 - t^{2} d t

\int_{1}^{3} (\frac{6}{x} - e^{- x}) d x

\int_{0}^{6} (9 x^{2} + x - 5) d x

\int_{0}^{x} \frac{1}{( 1 - x ) ( 2 - x )} d x

\int_{- 2}^{1} (2 x^{2} + 7) d x

What is the integral from 0 to 1 of e^{sin(x)}cos(x) ?
The integral from 0 to 1 of e^{sin(x)}cos(x) is e^{sin(1)}-1