What is the integral from 20 to x of 1/x ?

The integral from 20 to x of 1/x is ln|x|-ln(20)

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integral from 20 to x of 1/x

\int_{20}^{x} \frac{1}{x} d x

ln ∣ x ∣ - ln (20)

Solution steps

\int_{20}^{x} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{20}^{x}

Compute the boundaries:

ln ∣ x ∣ - ln (20)

= ln ∣ x ∣ - ln (20)

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\int_{3}^{4} x^{2} + 2 x + 2 - 8 d x

\int_{0}^{X} \frac{1}{1 - X} d X

\int_{- π}^{π} x sin (m x) d x

\int_{1}^{x^{2}} \frac{ln ( t )}{t} d t

What is the integral from 20 to x of 1/x ?
The integral from 20 to x of 1/x is ln|x|-ln(20)