What is the tangent of f(x)=10xsin(x),\at x= pi/2 ?

The tangent of f(x)=10xsin(x),\at x= pi/2 is y=10x

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tangent of f(x)=10xsin(x),\at x= pi/2

tangent of

f (x) = 10 x sin (x), at x = \frac{π}{2}

y = 10 x

Solution steps

Find the tangent point:

(\frac{π}{2}, 5 π)

Find the slope of

f (x) = 10 x sin (x) : \frac{df ( x )}{d x} = 10 (sin (x) + x cos (x))

Compute the slope of

f (x) = 10 x sin (x)

x = \frac{π}{2} : m = 10

Find the line with slope m=

10

and passing through

(\frac{π}{2}, 5 π) : y = 10 x

y = 10 x

\frac{\partial}{\partial x} (\frac{1}{4 - x ^{2}})

x \to 0 lim (\frac{x ^{2}}{x ^{4}})

\frac{d}{d x} (x^{3} - 3 x^{2} - 8 x + 2)

\frac{d}{d x} (\frac{3 x ^{2}}{2 x})

\frac{\partial}{\partial x} (x^{2} cos (x y + 2 x z - 3 yz))

What is the tangent of f(x)=10xsin(x),\at x= pi/2 ?
The tangent of f(x)=10xsin(x),\at x= pi/2 is y=10x