en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (3x+1)

Solution

\int_{0}^{1} (3 x + 1) d x

Solution

\frac{5}{2}

+1

Decimal

2.5

Solution steps

\int_{0}^{1} 3 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 3 x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 3 x d x = \frac{3}{2}

\int_{0}^{1} 1 d x = 1

= \frac{3}{2} + 1

Simplify

\frac{3}{2} + 1 : \frac{5}{2}

= \frac{5}{2}

Graph

Popular Examples

integral from 0 to 2 of 2^{4x}

\int_{0}^{2} 2^{4 x} d x

integral from 0 to 1 of t3^{t^2}

\int_{0}^{1} t 3^{t^{2}} d t

integral from 0 to 4 of (1+3y-y^2)

\int_{0}^{4} (1 + 3 y - y^{2}) d y

integral from 0 to 2 of (xe^{x^2})

\int_{0}^{2} (x e^{x^{2}}) d x

integral from 0 to 2pi of cos(mx)

\int_{0}^{2 π} cos (m x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (3x+1) ?
The integral from 0 to 1 of (3x+1) is 5/2