What is the integral from 1 to 9 of 1/(sqrt(5x+4)) ?

The integral from 1 to 9 of 1/(sqrt(5x+4)) is 8/5

Popular >

integral from 1 to 9 of 1/(sqrt(5x+4))

\int_{1}^{9} \frac{1}{5 x + 4} d x

\frac{8}{5}

Decimal

1.6

Solution steps

\int_{1}^{9} \frac{1}{5 x + 4} d x

Apply u-substitution

: \int_{9}^{49} \frac{1}{5 u} d u

= \int_{9}^{49} \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int_{9}^{49} \frac{1}{u} d u

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{9}^{49}

= \frac{1}{5} [2 u^{\frac{1}{2}}]_{9}^{49}

Apply radical rule:

a^{\frac{1}{n}} = n a

= \frac{1}{5} [2 u]_{9}^{49}

Compute the boundaries:

8

= \frac{1}{5} \cdot 8

Simplify

= \frac{8}{5}

\int_{0}^{4} 2 x - \frac{1}{4} x^{2} d x

\int_{0}^{3} 6 x e^{x^{2}} d x

\int_{- π}^{π} t cos (t) d t

\int_{1}^{8} (3 x + 5) d x

\int_{2}^{5} x^{2} - 4 d x

What is the integral from 1 to 9 of 1/(sqrt(5x+4)) ?
The integral from 1 to 9 of 1/(sqrt(5x+4)) is 8/5