What is the integral from 0 to 1 of-2x^2 ?

The integral from 0 to 1 of-2x^2 is -2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of-2x^2

\int_{0}^{1} - 2 x^{2} d x

- \frac{2}{3}

Decimal

- 0.66666 \dots

Solution steps

\int_{0}^{1} - 2 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= - 2 [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= - 2 \cdot \frac{1}{3}

Simplify

= - \frac{2}{3}

\int_{0}^{1} x (x^{2} + 2) d x

\int_{- k}^{k} ∣ k x ∣ d x

\int_{0}^{1} e^{x} - e^{2 x - 1} d x

\int_{0}^{\frac{3}{2}} \frac{x - 3}{2 x - 3} d x

\int_{0}^{\frac{π}{2}} 1 + cos (2 x) d x

What is the integral from 0 to 1 of-2x^2 ?
The integral from 0 to 1 of-2x^2 is -2/3