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Popular >

integral from 1 to 2 of 8-2x

Solution

\int_{1}^{2} 8 - 2 x d x

Solution

5

Solution steps

\int_{1}^{2} 8 - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 8 d x - \int_{1}^{2} 2 x d x

\int_{1}^{2} 8 d x = 8

\int_{1}^{2} 2 x d x = 3

= 8 - 3

Simplify

= 5

Graph

Popular Examples

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\int_{\frac{π}{3}}^{π} sin (2 x) d x

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\int_{- π}^{0} 6 x^{2} d x

integral from 0 to 1 of 6x^5(4-x^6)

\int_{0}^{1} 6 x^{5} (4 - x^{6}) d x

integral from-1 to 1 of e^{-2x}-1

\int_{- 1}^{1} e^{- 2 x} - 1 d x

integral from 0 to pi of sqrt(x)-sin(x)

\int_{0}^{π} x - sin (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of 8-2x ?
The integral from 1 to 2 of 8-2x is 5