What is the integral from 0 to 1 of (5x^2-8x+9) ?

The integral from 0 to 1 of (5x^2-8x+9) is 20/3

Popular >

integral from 0 to 1 of (5x^2-8x+9)

\int_{0}^{1} (5 x^{2} - 8 x + 9) d x

\frac{20}{3}

Decimal

6.66666 \dots

Solution steps

\int_{0}^{1} 5 x^{2} - 8 x + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 5 x^{2} d x - \int_{0}^{1} 8 x d x + \int_{0}^{1} 9 d x

\int_{0}^{1} 5 x^{2} d x = \frac{5}{3}

\int_{0}^{1} 8 x d x = 4

\int_{0}^{1} 9 d x = 9

= \frac{5}{3} - 4 + 9

Simplify

\frac{5}{3} - 4 + 9 : \frac{20}{3}

= \frac{20}{3}

\int_{0}^{1} (x^{2} - x + 1) e^{2 x} d x

\int_{0}^{1} \frac{1}{( x ^{2} - 1 )} d x

\int_{5}^{7} x^{2} + x + 1 - 15 d x

\int_{- 8}^{8} ∣ 7 x ∣ - (x^{2} - 8) d x

\int_{2}^{4} 5 x^{4} + 8 x^{3} d x

What is the integral from 0 to 1 of (5x^2-8x+9) ?
The integral from 0 to 1 of (5x^2-8x+9) is 20/3