What is the integral from-1 to x of e^t ?

The integral from-1 to x of e^t is e^x-1/e

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to x of e^t

\int_{- 1}^{x} e^{t} d t

e^{x} - \frac{1}{e}

Solution steps

\int_{- 1}^{x} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= [e^{t}]_{- 1}^{x}

Compute the boundaries:

e^{x} - \frac{1}{e}

= e^{x} - \frac{1}{e}

\int_{0}^{7} (x^{2} - 4) d x

\int_{3}^{u} \frac{1}{x + x ^{2}} d x

\int_{1}^{9} \frac{x - 6}{x} d x

\int_{- π}^{π} x sin (k x) d x

\int_{0}^{5} x (3) d x

What is the integral from-1 to x of e^t ?
The integral from-1 to x of e^t is e^x-1/e