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Popular >

integral from 0 to 1 of ax+b

Solution

\int_{0}^{1} a x + b d x

Solution

\frac{a}{2} + b

Solution steps

\int_{0}^{1} a x + b d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} a x d x + \int_{0}^{1} b d x

\int_{0}^{1} a x d x = \frac{a}{2}

\int_{0}^{1} b d x = b

= \frac{a}{2} + b

Popular Examples

integral from-1 to 1 of sec^3(x)tan^3(x)

\int_{- 1}^{1} sec^{3} (x) tan^{3} (x) d x

integral from 0 to (3pi)/4 of tan(x/3)

\int_{0}^{\frac{3 π}{4}} tan (\frac{x}{3}) d x

integral from-2 to 1 of (5x^2-7x+3)

\int_{- 2}^{1} (5 x^{2} - 7 x + 3) d x

integral from-1 to 4 of (3x^4-4x^3-x-4)

\int_{- 1}^{4} (3 x^{4} - 4 x^{3} - x - 4) d x

integral from 0 to 2 of (6x-6)(8x^2+2)

\int_{0}^{2} (6 x - 6) (8 x^{2} + 2) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of ax+b ?
The integral from 0 to 1 of ax+b is a/2+b