What is the integral from 0 to 6 of-3x^2-12x+180 ?

The integral from 0 to 6 of-3x^2-12x+180 is 648

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 6 of-3x^2-12x+180

\int_{0}^{6} - 3 x^{2} - 12 x + 180 d x

648

Solution steps

\int_{0}^{6} - 3 x^{2} - 12 x + 180 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{6} 3 x^{2} d x - \int_{0}^{6} 12 x d x + \int_{0}^{6} 180 d x

\int_{0}^{6} 3 x^{2} d x = 216

\int_{0}^{6} 12 x d x = 216

\int_{0}^{6} 180 d x = 1080

= - 216 - 216 + 1080

Simplify

= 648

\int_{0}^{1} 2 x^{3} e^{- x^{2}} d x

\int_{- π}^{π} cos^{2} (k) x d x

\int_{1}^{10} (\frac{5}{x}) d x

\int_{0}^{1} 4 y^{2} (1 - y^{2}) d y

\int_{1}^{\infty} \frac{7}{x ^{2}} d x

What is the integral from 0 to 6 of-3x^2-12x+180 ?
The integral from 0 to 6 of-3x^2-12x+180 is 648