What is the integral from 1 to 5 of 2/(t^3) ?

The integral from 1 to 5 of 2/(t^3) is 24/25

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integral from 1 to 5 of 2/(t^3)

\int_{1}^{5} \frac{2}{t ^{3}} d t

\frac{24}{25}

Decimal

0.96

Solution steps

\int_{1}^{5} \frac{2}{t ^{3}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{5} \frac{1}{t ^{3}} d t

Apply the Power Rule

: [- \frac{1}{2 t ^{2}}]_{1}^{5}

= 2 [- \frac{1}{2 t ^{2}}]_{1}^{5}

Compute the boundaries:

\frac{12}{25}

= 2 \cdot \frac{12}{25}

Simplify

= \frac{24}{25}

\int_{- 1}^{1} 1 + x + x^{2} + x^{3} d x

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\int_{1}^{4} 1 + x d x

\int_{0}^{6} 6 y^{3} - 6 y^{2} d y

\int_{0}^{16} (2 x) d x

What is the integral from 1 to 5 of 2/(t^3) ?
The integral from 1 to 5 of 2/(t^3) is 24/25