What is the integral from 0 to 8.13 of 1000x+250 ?

The integral from 0 to 8.13 of 1000x+250 is 35080.95

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integral from 0 to 8.13 of 1000x+250

\int_{0}^{8.13} 1000 x + 250 d x

35080.95

Solution steps

\int_{0}^{8.13} 1000 x + 250 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8.13} 1000 x d x + \int_{0}^{8.13} 250 d x

\int_{0}^{8.13} 1000 x d x = 33048.45

\int_{0}^{8.13} 250 d x = 2032.5

= 33048.45 + 2032.5

Simplify

= 35080.95

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What is the integral from 0 to 8.13 of 1000x+250 ?
The integral from 0 to 8.13 of 1000x+250 is 35080.95